First slide

Variation of g

Question

If R is radius of the earth, the height above the surface of the earth where the weight of a body is 36% less than its weight on the surface of the earth is

Easy

A

4R/5
B

R/5
C

R/6
D

R/4

Solution

Weight at a height h is 64% of the weight at the surface of earth.
$\large {g}'=\frac {g}{\left ( 1+\frac hR \right )^2}\Rightarrow64=\frac {100}{\left ( 1+\frac hR \right )^2};h=\frac R4$

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