Q.
If R is the radius of earth, ω is its angular velocity and gp is the value of acceleration due to gravity at the poles, then effective value of acceleration due to gravity at the latitude λ=60∘ will be equal to
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a
gp−14Rω2
b
gp−34Rω2
c
gp−Rω2
d
gp+14Rω2
answer is A.
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Detailed Solution
g′=gp−Rω2cos2λ,λ=60∘,g′=gp−Rω24
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