If R is the radius of earth, ω is its angular velocity and gp is the value of acceleration due to gravity at the poles, then effective value of acceleration due to gravity at the latitude λ=60∘ will be equal to

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gp−14Rω2

gp−34Rω2

gp−Rω2

gp+14Rω2

answer is A.

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Detailed Solution

g′=gp−Rω2cos2⁡λ,λ=60∘,g′=gp−Rω24

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