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If R is the radius of earth, ω is its angular velocity and gp is the value of acceleration due to gravity at the poles, then effective value of acceleration due to gravity at the latitude λ=60 will be equal to

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By Expert Faculty of Sri Chaitanya
a
gp−14Rω2
b
gp−34Rω2
c
gp−Rω2
d
gp+14Rω2

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detailed solution

Correct option is A

g′=gp−Rω2cos2⁡λ,λ=60∘⋅g′=gp−Rω24
ctaimg

ctaimg

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