If R is the radius of earth, ω is its angular velocjty and gp is the value of g at the poles. The effective value of g at a latitude λ = 600 is [JIPMER 2018]
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a
gp-14Rω2
b
gp+14Rω2
c
gp-12Rω2
d
gp+12Rω2
answer is A.
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Detailed Solution
The acceleration due to gravity at a latitude λ isg'=g-Rω2cos2λAt the poles, λ=90° ∴ g=g=gp ∵cos90°=0For λ=60°, g'=gp-Rω2cos2λor g'=gp-Rω2cos260°Hence, g'=gp-Rω2122=gp-14Rω2