First slide

Variation of g

Question

If R is radius of earth then the height above earth surface at which acceleration due to gravity reduces by 75% of its value on earth surface :

Moderate

A

R/2
B

2R
C

3R
D

R

Solution

75 % of g reduces means
$g^{'} = 27 % of g^{'} = \frac{g}{4}$
$g^{'} = \frac{g}{{(1 + \frac{h}{R})}^{2}} = \frac{g}{4} \Rightarrow h = R$

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