Questions
If 10% of a radioactive material decays in 5 days, then the amount of original material left after 20 days is approximately
detailed solution
Correct option is B
N=N0e-λt ∴0.9N0=N0e-λ x 5⇒5λ=loge10.9 .........(i) and xN0=N0e-λ x 20⇒20λ=loge1x .........(ii)Dividing (i) by (ii) we get14=loge(1/0.9)loge(1/x)=log10(1/0.9)log10(1/x)=log10 0.9log10 x ⇒log10 x=4 log10 0.9⇒x=0.658=65.8%Talk to our academic expert!
Similar Questions
The half life period of a radioactive element X is same as the mean life time of another radioactive element Y. Initially both of them have the same number of atoms. Then
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