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If a radioactive sample initially contains $8.00 \times 10^{14}$ parent nuclei with a half life of 7.00 hr’s , how many parent nuclei remain in 24.0 hr’s later ?

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5.42×1012

7.43×1013

6.00×1013

4.00×1014

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detailed solution

Correct option is B

Decay Law , N=No12t/T⇒N=8.00×1014×1224/7⇒N=8.00×1014×12.3.42⇒N=8.00×1014×110.76⇒N=7.43×1013

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If a radioactive sample initially contains 8.00 ×1014 parent nuclei with a half life of 7.00 hr’s , how many parent nuclei remain in 24.0 hr’s later ?

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If a radioactive sample initially contains $8.00 \times 10^{14}$ parent nuclei with a half life of 7.00 hr’s , how many parent nuclei remain in 24.0 hr’s later ?