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If a radioactive substance reduces to $\frac{1}{16}$ of its original mass in 40 days, what is its halt-life?

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Correct option is A

NN0=12n⇒116=124=12n⇒n=4 Also n=tT1/2⇒T1/2=404=10 days

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If a radioactive substance reduces to 116 of its original mass in 40 days, what is its halt-life?

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If a radioactive substance reduces to $\frac{1}{16}$ of its original mass in 40 days, what is its halt-life?