Question

If radius of earth shrinks by 0.1% without change in its mass, the percentage change in the duration of one day

Moderate

Solution

$\begin{array}{l} Iω = \frac{2}{5} {MR}^{2} \times (\frac{2 π}{T}) = constant \\ T \propto R^{2} and \frac{ΔT}{T} = 2 \frac{ΔR}{R} \end{array}$

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