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If radius of 1327Aℓ nucleus is estimated to be 3.6 fermi, then the radius of 52125X nucleus be nearly

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a

4 fermi

b

5 fermi

c

6 fermi

d

8 fermi

answer is C.

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Detailed Solution

R1R2=(A1A2)13 3.6R2=(27125)13=35 R2=53×3.6=6fermi

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