First slide

Introduction-Wave optics

Question

If the ratio of amplitude of two waves is 4 : 3, then the ratio of maximum and minimum intensity is

Easy

A

16 : 18
B

18 : 16
C

49 : 1
D

94 : 1

Solution

$\frac{I_{max}}{I_{min}} = {(\frac{\frac{a_{1}}{a_{2}} + 1}{\frac{a_{1}}{a_{2}} - 1})}^{2} = {(\frac{\frac{4}{3} + 1}{\frac{4}{3} - 1})}^{2} = \frac{49}{1}$

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