Q.

If the ratio of moment of inertia of two rings of radius. r1 and r2 is 0.25, then find the value of ratio r2r1.

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a

42/3

b

41/3

c

4−2/3

d

4−1/3

answer is B.

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Detailed Solution

Ratio of moments of inertia is given asI2I1=4and we know that I=mr2So I2I1=m2r22m1r12…(i)mass = volume × density,density and thickness of both loops are same here,So m∝2πr⇒m∝rSo from eq. (i)I2I1=r23r134I=r2r13⇒r2r1=(4)13
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If the ratio of moment of inertia of two rings of radius. r1 and r2 is 0.25, then find the value of ratio r2r1.