If the ratio of moment of inertia of two rings of radius. r1 and r2 is 0.25, then find the value of ratio r2r1.

Ratio of moments of inertia is given asI2I1=4and we know that I=mr2So I2I1=m2r22m1r12…(i)mass = volume × density,density and thickness of both loops are same here,So m∝2πr⇒m∝rSo from eq. (i)I2I1=r23r134I=r2r13⇒r2r1=(4)13