First slide

Prism

Question

If the refractive index of a material of equilateral prism is $\sqrt{3}$ , then angle of minimum deviation of the prism is

Moderate

A

30°
B

45°
C

60°
D

75°

Solution

$μ = \frac{\sin (\frac{A + δ_{m}}{2})}{\sin \frac{A}{2}} \Rightarrow \sqrt{3} = \frac{\sin (\frac{60^{\circ} + δ_{m}}{2})}{\sin \frac{60^{\circ}}{2}} \Rightarrow \frac{\sqrt{3}}{2} = \sin (30^{\circ} + \frac{δ_{m}}{2}) \Rightarrow δ_{m} = 60^{\circ}$

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