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Q.

If resistance of 100 Ω, inductance of 0.5 H and capacitance of 10×10−6 F are connected in series through 50 Hz AC supply, then impedance is

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a

1.876 Ω

b

18.76 Ω

c

189.72 Ω

d

101.3 Ω

answer is C.

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Detailed Solution

Z=R2+XL−XC2=1002+0.5×100π−110×10−6×100π2=189.72 Ω
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If resistance of 100 Ω, inductance of 0.5 H and capacitance of 10×10−6 F are connected in series through 50 Hz AC supply, then impedance is