First slide

AC Circuits

Question

If resistance of 100 $Ω$ , inductance of 0.5 henry and capacitance of $10 \times 10^{- 6} F$ are connected in series through 50 Hz ac supply, then impedance is

Moderate

A

1.876
B

18.76
C

189.72
D

101.3

Solution

$Z = \sqrt{R^{2} + {(X_{L} - X_{C})}^{2}}$
$= \sqrt{100^{2} + {(0 .5 \times 100 π - \frac{1}{10 \times 10^{- 6} \times 100 π})}^{2}} = 189 .72 Ω$

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