Download the app

Questions  

If rest mass of helium nucleus is 4.0015 u, rest mass of proton is 1.0087 u, then binding energy of  24He nucleus is 

a
28.41 MeV
b
26.37 MeV
c
32.15 MeV
d
18.36 MeV

detailed solution

Correct option is A

Binding energy of nucleus = Initial rest mass energy of its constituents - Rest mass energy of the nucleus=21.0073+1.0087−4.0015u×c2=0.0305×931.5/c2×c2 MeV=28.41 MeV

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

In the circuit shown in figure, current through the conductor BC is


phone icon
whats app icon