First slide

Nuclear Binding energy

Question

If rest mass of helium nucleus is 4.0015 u, rest mass of proton is 1.0087 u, then binding energy of $_{2}^{4} He$ nucleus is

Moderate

A

28.41 MeV
B

26.37 MeV
C

32.15 MeV
D

18.36 MeV

Solution

Binding energy of nucleus
= Initial rest mass energy of its constituents - Rest mass energy of the nucleus
$= [2 (1 .0073 + 1 .0087) - 4 .0015] u \times c^{2}$
$= 0 .0305 \times (931 .5 / c^{2}) \times c^{2} MeV$
$= 28 .41 MeV$

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