If rest mass of helium nucleus is 4.0015 u, rest mass of proton is 1.0087 u, then binding energy of  24He nucleus is

Binding energy of nucleus = Initial rest mass energy of its constituents - Rest mass energy of the nucleus=21.0073+1.0087−4.0015u×c2=0.0305×931.5/c2×c2 MeV=28.41 MeV