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If retardation produced by air resistance of projectile is 1/10 of acceleration due to gravity, the time to reach maximum height

a
decreases by 11%
b
increases by 11%
c
decreases by 9%
d
increases by 9%

detailed solution

Correct option is C

We know that,T=usin⁡θ/gIf a is retardation caused due to air resistance, then total retardation, a' = (g + a). NowT′=usin⁡θ(g+a)Substituting a = (g / 10), we getT′=usin⁡θ[g+(g/10)]=10usin⁡θ11g=1011TThe percentage decrease in time is given byT−T′T×100=T−(10T/11)T×100=9%

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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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