If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1 %. If the density of the water is 1×103 kg/m3 and g = 10 m/s2, then the volume elasticity in N/m2 will be

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108

2 × 108

109

2 × 109

answer is D.

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Detailed Solution

K = ∆P∆VV = hρg∆VV= 200×103×100.1100 = 2 ×109

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