First slide

Fluid statics

Question

If a sample of metal weighs 210 g in air, 180 g in water and 120 g in a liquid:
(i) RD of metal is 3
(ii) RD of metal is 7
(iii) RD of liquid is 3
(iv) RD of liquid is ( 1/3)

Moderate

A

(i, ii)
B

(i, iii)
C

(ii, iv)
D

(ii, iii)

Solution

$R.D of metal = \frac{W_{A}}{W_{A} - W_{w}} = \frac{210 g}{210 g - 180 g} = 7 R . D of liquid = \frac{W_{A} - W_{L}}{W_{A} - W_{W}} = \frac{210 g - 120 g}{210 g - 180 g} = 3$

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