If the screw on a screw – gauge is given six rotations, it moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is :

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0.001 mm

0.001cm

0.01 cm

0.02 mm

answer is B.

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Detailed Solution

Pitch=3 mm6=0.5 mmLC=pitchno.of CSD's=0.5 mm50=0.001 cm

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