First slide

Measurement

Question

If the screw on a screw – gauge is given six rotations, it moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is :

Easy

A

0.001 mm
B

0.001cm
C

0.01 cm
D

0.02 mm

Solution

$\begin{array}{l} P i t c h = \frac{3 m m}{6} = 0.5 m m \\ L C = \frac{p i t c h}{n o . o f C S D' s} = \frac{0.5 m m}{50} = 0.001 c m \end{array}$

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