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If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band gap energy is :
Planck’s constant $h = 6.63 \times 10^{- 34} J . s$ . Speed of light $c = 3 \times 10^{8} m / s$

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detailed solution

Correct option is B

Band gap = Energy of photon = hcλ=12400/λ in AoBand gap = 4.14×10−15×3×1084×10−7ev=3.1ev

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If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band gap energy is :Planck’s constant h=6.63×10−34J.s. Speed of light c=3×108m/s

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band gap energy is :
Planck’s constant $h = 6.63 \times 10^{- 34} J . s$ . Speed of light $c = 3 \times 10^{8} m / s$