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Q.

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400nm, then its band gap energy is :Planck’s constant h=6.63×10−34J.s. Speed of light c=3×108m/s

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a

1.1eV

b

3.1eV

c

2.0eV

d

1.5eV

answer is B.

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Detailed Solution

Band gap = Energy of photon =  hcλ=12400/λ in AoBand gap =   4.14×10−15×3×1084×10−7ev=3.1ev
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