Q.

If the series limit wavelength of the Lyman series for hydrogen atom is 912 Å, then the series limit wavelength for the Balmer series for the hydrogen atom is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

912Å/2

b

912Å

c

912×2Å

d

912×4Å

answer is D.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

For Lyman series, the series limit wavelength is given by1λ=R112−1∞2=R  or  λ=1RFor Balmer series, the series limit wavelength is given by1λ′=R122−1∞2=R4  or  λ′=4RClearly,          λ′=41R  or  λ′=4λ=4×912Å
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon