Q.
If the series limit wavelength of the Lyman series for hydrogen atom is 912 Å, then the series limit wavelength for the Balmer series for the hydrogen atom is
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a
912Å/2
b
912Å
c
912×2Å
d
912×4Å
answer is D.
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Detailed Solution
For Lyman series, the series limit wavelength is given by1λ=R112−1∞2=R or λ=1RFor Balmer series, the series limit wavelength is given by1λ′=R122−1∞2=R4 or λ′=4RClearly, λ′=41R or λ′=4λ=4×912Å
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