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If the series limit wavelength of the Lyman series for hydrogen atom is 912 A0, then the series limit wavelength for the Balmer series for the hydrogen atom is

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a
912 A0
b
912 x 3A0
c
912 x 2A0
d
912 x 4A0

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detailed solution

Correct option is D

For Lyman series, the series limit wavelength is given by1λ=R112−1∞2=R  or  λ=1RFor Balmer series, the series limit wavelength is given by1λ'=R122−1∞2=R4    or    λ'=4RClearly,   λ'=41R     or    λ'=4λ


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