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Q.

If the series limit wavelength of the Lyman series for hydrogen atom is 912 A0, then the series limit wavelength for the Balmer series for the hydrogen atom is

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a

912 A0

b

912 x 3A0

c

912 x 2A0

d

912 x 4A0

answer is D.

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Detailed Solution

For Lyman series, the series limit wavelength is given by1λ=R112−1∞2=R  or  λ=1RFor Balmer series, the series limit wavelength is given by1λ'=R122−1∞2=R4    or    λ'=4RClearly,   λ'=41R     or    λ'=4λ
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