If the series limit wavelength of the Lyman series for hydrogen atom is 912 A0, then the series limit wavelength for the Balmer series for the hydrogen atom is
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a
912 A0
b
912 x 3A0
c
912 x 2A0
d
912 x 4A0
answer is D.
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Detailed Solution
For Lyman series, the series limit wavelength is given by1λ=R112−1∞2=R or λ=1RFor Balmer series, the series limit wavelength is given by1λ'=R122−1∞2=R4 or λ'=4RClearly, λ'=41R or λ'=4λ