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If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is
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Correct option is B
vmax=aω=a×2πT=(50×10−3)×2π2=0.15 m/sSimilar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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