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Q.

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

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a

0.10 m / s

b

0.15 m / s

c

0.8 m / s

d

0.26 m / s

answer is B.

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Detailed Solution

vmax=aω=a×2πT=(50×10−3)×2π2=0.15 m/s
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