Q.

If the speed of sound through hydrogen is 1280 m/s, what will be the speed of sound (in m/s) through a mixture of 4 parts by volume of hydrogen and 1 part of oxygen? Given density of oxygen is 16 times that of hydrogen

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 640.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

If V is the volume of the mixture,Volume of hydrogen =45VAnd volume of oxygen =15VMass of oxygen =15VρO=V516ρH as ρO=16ρHTotal mass of the mixture, mmix =45VρH+V516ρH=4VρHDensity of mixture, ρm=4VρHV=4ρHThus, vmvH=ρHρm=14=12or vm=12vH=12×1280=640 m/s
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
If the speed of sound through hydrogen is 1280 m/s, what will be the speed of sound (in m/s) through a mixture of 4 parts by volume of hydrogen and 1 part of oxygen? Given density of oxygen is 16 times that of hydrogen