First slide

Dimensions of physical quantities

Question

If speed V, area A and force F are chosen as fundamental units, then the dimension of Young’s modulus will be:

Easy

A

$F A^{- 1} V^{0}$
B

$F A^{2} V^{- 2}$
C

$F A^{2} V^{- 3}$
D

$F A^{2} V^{- 1}$

Solution

Using formulae for longitudinal stress,
$\frac{F}{A} = Y \frac{Δ l}{l}, A s s t r e s s i s d i m e n s i o n l e s s, \Rightarrow [Y] = [F] . {[A]}^{- 1}$

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