If the speed of the wave shown in the figure is 330 m/s in the given medium, then the equation of the wave propagating in the positive x-direction will be (all quantities are in M.K.S. units)
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a
y=0.05sin2π(4000 t−12.5 x)
b
y=0.05sin2π(4000 t−122.5 x)
c
y=0.05sin2π(3300 t−10 x)
d
y=0.05sin2π(3300 x−10 t)
answer is C.
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Detailed Solution
Here A=0.05 m,5λ2=0.25⇒λ=0.1mNow standard equation of wave y=A sin2πλ(vt−x)⇒y=0.05sin2π(3300t−10x)
If the speed of the wave shown in the figure is 330 m/s in the given medium, then the equation of the wave propagating in the positive x-direction will be (all quantities are in M.K.S. units)