First slide

Applications of SHM

Question

If a spring of force constant 'K' is cut into three equal parts then the force constant of each part will be

Easy

A

$\frac{K}{3}$
B

$K$
C

$3 K$
D

$6 K$

Solution

$F o r c e o f s p r i n g i s F = K x F o r c e i s c o n s \tan t K x = c o n s \tan t, K i s f o r c e c o n s \tan t K l = c o n s \tan t, w h e r e l = l e n g t h o f t h e s p r i n g - - - - (1) i f l e n g t h = \frac{l}{3}, t h e n n e w f o r c e c o n s \tan t i s k^{'}, K^{'} \frac{l}{3} = c o n s \tan t - - - - - - (2) K' \frac{l}{3} =Kl \Rightarrow K^{'} = 3 K$

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