Q.

If a steady current I is flowing through a cylindrical element ABC. Choose the correct relationship :

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

VAB = 2VBC

b

Power across BC is 4 times the power across AB

c

Current densities in AB and BC are equal

d

Electric field due to current inside AB and BC are equal

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

RB1=V2100, RB2=RB3=V260Current in bulbs I1=I2=250RB1+RB2=250 x 3008V2and I3=250RB3=250 x 60V2Power in bulbs W1=I12RB1, W2=I22RB2, W3=I32RB3⇒W1 : W2 : W3=250 x 3008V22V2100 : 250 x 3008V2V260 : 250 x 60V22V260= 15 : 25 : 64
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon