If a stone is to hit at a point which is at a distance d away and at a height h (see fig) above the point from where the stone starts, then what is the value of initial speed u if the stone is launched at an angle θ ?
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a
dsinθg2(dtanθ-h)
b
dcosθg2(dtanθ-h)
c
gd2hcos2θ
d
gd2(d-h)
answer is B.
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Detailed Solution
General equation of trajectory of a projectile is y = x tan θ - gx22u2 cos α2 . Putting x= d and y = h , h=d tan θ - gd22u2cos θ2 Solving , u =dcos θ g2d tan θ-h