If a stone is to hit at a point which is at a distance d away and at a height h (see figure) above the point from where the stone starts, then what is the value of initial speed u if the stone is launched at an angle θ?
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a
gcosθd2(dtanθ−h)
b
dcosθg2(dtanθ−h)
c
gd2hcos2θ
d
gd2(d−h)
answer is B.
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Detailed Solution
h=(usinθ)t−12gt2d=(ucosθ)t or t=ducosθh=usinθducosθ−12gd2u2cos2θu=dcosθg2(dtanθ−h)