If the sum of two unit vectors is a unit vector, then magnitude of difference is
2
3
1/2
5
Let n^1 and n^2 are the two unit vectors, then the sum is
n→s=n^1+n^2 Magnitude of n→s is given by ns2=n12+n22+2n1n2cosθ=1+1+2cosθ
Since it is given that ns is also a unit vector, therefore
1=1+1+2cosθ⇒cosθ=−12∴θ=120∘
Now the difference vector is
n^d=n^1−n^2 Magnitude of n^d is given by nd2=n12+n22−2n1n2cosθ=1+1−2cos120∘⇒nd2=2−2(−1/2)=2+1=3⇒nd=3