Q.

If the temperature of the hot body is increased by 50%. The percentage of amount of radiation emitted is increased by

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50%

400%

250%

500%

answer is 2.

(Detailed Solution Below)

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Detailed Solution

let initial temperature of the hot body beT1=100K: temperature increased by 50%, then final temperature isT2=150K let initial energy radiated be E1=E; final energy is E2 percentage increase of amount of radiation emitted=? ΔEE×100=? ΔE=E2-E1 from stefans law E=σT4 ⇒EαT4 ⇒E2E1=T2T14 ⇒E2E1=1501004 subtract 1 from each side E2E1-1=8116-1 E2-E1E1=81-1616 multiply by 100 both side , to get percentage ΔEE×100=6516×100=406%≈400% percentage increase of amount of radiation emitted=400%

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