First slide
Viscosity
Question

 If the terminal speed of a sphere of gold (density =195kg/m3 ) is 0.2m/ s in viscous liquid (density =15kg/m3 find the terminal speed of a sphere of silver (density = 10.5kg/m3 ) of the same size in the same liquid 

Moderate
Solution

we know that 
VT=29r2(ρσ)gη in the present case  vTAgvTAu=ρAgσlρAuσl  vTAg=vTAu×ρAgσlρAuσl =02×(10515)(19515) =02×918=02×12=01m/s

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