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Q.

If 78th part of a radio active element decays in 168 sec, its half life is

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a

16 S

b

56 S

c

128 S

d

21 S

answer is B.

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Detailed Solution

N=N0(2)t/t1/2∴N0−7N08=N0(2)t/t1/2⇒(2)t/t1/2=8=(2)3∴t1/2=t3=1683sec=56 sec
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