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If $\frac{7}{8}$ th part of a radio active element decays in 168 sec, its half life is

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Correct option is B

N=N0(2)t/t1/2∴N0−7N08=N0(2)t/t1/2⇒(2)t/t1/2=8=(2)3∴t1/2=t3=1683sec=56 sec

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If 78th part of a radio active element decays in 168 sec, its half life is

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If $\frac{7}{8}$ th part of a radio active element decays in 168 sec, its half life is