If θ = 120º , then
sinθ=32
cosθ=12
cotθ=12
tanθ=3
sin120=sin 180-60°=sin 60=32 ∵Sine is positive in II quadrant cos120=cos 180-60°=-cos 60=-12 ∵cosine is negative in II quadrant cot120=cot 180-60°=-cot 60=-13 ∵cot is negative in II quadrant tan120=tan 180-60°=-tan 60=-3 ∵tan is negative in II quadrant