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Questions  

If θ = 120º , then

a
sin⁡θ=32
b
cos⁡θ=12
c
cot⁡θ=12
d
tan⁡θ=3

detailed solution

Correct option is A

sin⁡120=sin 180-60°=sin 60=32 ∵Sine is positive in II quadrant cos⁡120=cos 180-60°=-cos 60=-12 ∵cosine is negative in II quadrant cot⁡120=cot 180-60°=-cot 60=-13 ∵cot is negative in II quadrant  tan⁡120=tan 180-60°=-tan 60=-3 ∵tan is negative in II quadrant

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Similar Questions

Which of the following values are positive?

 (a) cos120°

 (b) sin210°

 (c) tan240°

 (d) cos315°


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