First slide

Motion in a plane

Question

If $\large \vec C\$ = $\large \vec A\$ + $\large \vec B\$ then

Moderate

A

$\large \vec C\$ is always greater than | $\large \vec A\$ |
B

C is always equal to A+B
C

C is never equal to A+B
D

It is possible to have | $\vec C\$ | < | $\vec A\$ | and | $\vec C\$ | < | $\vec B\$ |

Solution

$\large \vec C\$ = $\large \vec A\$ + $\large \vec B\$
If the angle between $\large \vec A\$ and $\large \vec B\$ is zero , i.e. $\large \vec A\$ and $\large \vec B\$ are parallel , then | $\large \vec C\$ | = A +B
If the angle between $\large \vec A\$ and $\large \vec B\$ is 180⁰ , i.e $\large \vec A\$ and $\large \vec B\$ are antiparallel, then | $\large \vec C\$ |_min = (A-B) or (B-A)
Here , (A-B) and (B-A) ,may be less than | $\large \vec A\$ | or | $\large \vec B\$ |
So , Option 4 is right

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