First slide

Calorimetry

Question

If there are no heat losses, the heat released by the condensation of x gm of steam at 100^oC into water at 100oC can be used to convert y gm of ice at 0^oC into water at 100^oC. Then the ratio y : x is nearly

Moderate

A

1:1
B

2.5:1
C

2:1
D

3:1

Solution

Heat released to convert x gm of steam at 100^oC to water at 100^oC is x $\times$ 540 cals.
If y gm of ice is converted from 0^oC to water at 100^oC it requires heat $y \times 80 + y \times 1 \times 100 = 180 y$
$∴ x \times 540 = 180 y or \frac{y}{x} = \frac{540}{180} = \frac{3}{1}$

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