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If there are no heat losses, the heat released by the condensation of x gm of steam at 100^oC into water at 100oC can be used to convert y gm of ice at 0^oC into water at 100^oC. Then the ratio y : x is nearly

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detailed solution

Correct option is D

Heat released to convert x gm of steam at 100oC to water at 100oC is x × 540 cals.If y gm of ice is converted from 0oC to water at 100oC it requires heat y×80+y×1×100=180y ∴ x×540=180y or yx=540180=31

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