First slide

Elastic Modulie

Question

If there is no change in the volume of wire on stretching, then Poisson's ratio for the material of wire is:

Moderate

A

-1
B

0
C

0.5
D

0.25

Solution

$\frac{∆ v}{v} = \frac{∆ l}{l} (1 - 2 σ) w h e n \frac{∆ v}{v} = 0 1 - 2 σ = 0 σ = 0.5$

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