If a thermometer reads freezing point of water as $$20$$∘c and boiling point is $$150$$∘c how much thermometer read, when the actual temperature is $$60$$∘c

Question

If a thermometer reads freezing point of water as  $$20$$∘c and boiling point is  $$150$$∘c how much thermometer read, when the actual temperature is  $$60$$∘c

Infinity Learn · Accepted Answer

unknown thermometer , Lower Fixed $$point(LFP)$$ $$=$$ $$200C$$; Upper Fixed Point $$(UFP)=1500C$$; actual reading given $$=$$ $$600C$$  the formula that relates unknown thermometer and celsius thermometer is, $$Z-LFPUFP-LFP=C-LFPUFP-LFP$$ celsius thermometer has $$LFP=00C$$ and $$UFP=1000C$$  substitute given values in above equation, x is reading on unknown thermometer  $$x-20150-20=60-0100-0$$  $$x-20=78$$  $$x=98$$∘c

If a thermometer reads freezing point of water as $20^{\circ} c$ and boiling point is $150^{\circ} c$ how much thermometer read, when the actual temperature is $60^{\circ} c$

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If a thermometer reads freezing point of water as 20∘c and boiling point is 150∘c how much thermometer read, when the actual temperature is 60∘c

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If a thermometer reads freezing point of water as $20^{\circ} c$ and boiling point is $150^{\circ} c$ how much thermometer read, when the actual temperature is $60^{\circ} c$