Q.
If a thermometer reads freezing point of water as 20°C and boiling point as 150°C. What will thermometer read when the actual temperature is 60°?
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a
98°C
b
110°C
c
40°C
d
60°C
answer is A.
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Detailed Solution
x−20150−20 = 60−0100−0 ⇒ x=98oC
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