First slide

Thermometry

Question

If a thermometer reads freezing point of water as 20^o C and boiling point as 150^o C , how much will thermometer read when the actual temperature is 60^oC ?

Easy

A

98^oC
B

110^oC
C

40^oC
D

120^oC

Solution

$\begin{array}{l} \frac{60}{100} = \frac{X - 20}{130} \\ 78 = X - 20 \\ X = 98 \end{array}$

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