If a thermometer reads freezing point of water as 20^o C and boiling point as 150^o C , how much will thermometer read when the actual temperature is 60^oC ?

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98oC

110oC

40oC

120oC

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detailed solution

Correct option is A

60100=X−2013078=X−20X=98

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A centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{0} F .$ What is the temperature as registered by the centigrade thermometer?

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If a thermometer reads freezing point of water as 20o C and boiling point as 150o C , how much will thermometer read when the actual temperature is 60oC ?

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If a thermometer reads freezing point of water as 20^o C and boiling point as 150^o C , how much will thermometer read when the actual temperature is 60^oC ?