If a thin prism of glass is dipped into water then minimum deviation (with respect to air) of light produced by prism will be left $\left({\mathrm{a\mu }}_{\mathrm{g}}=\frac{3}{2}\text{ and }{\mathrm{a\mu }}_{\mathrm{w}}=\frac{4}{3}\right)$  

• A

  $\frac{1}{2}$

• B

  $\frac{1}{4}$

• C

  $2$

• D

  $\frac{1}{5}$