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Questions  

If three vectors xa2b+3c , 2a+yb4c  and zb+2c  are coplanar, where a , b  and c  are unit (or any) vectors, then:

a
xy+3zx−3x=4
b
2xy−2zx−3z−4=0
c
4xy−3zx+3z=4
d
xy−2zx+3z−4=0

detailed solution

Correct option is D

Conditions of coplanarity, coplanar vectors have scalar triple product as zero A→.(B→×C→)=0 or |x−23−2y−40−z2|=0 or x(2y−4z)+2(−4−0)+3(2z−0)=0 or 2xy−4zx−8+6z=0 or xy−2zx+3z−4=0

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If A×B=C+D  then select the correct alternative (s):


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