If three vectors xa→−2b→+3c→ , −2a→+yb→−4c→ and −zb→+2c→ are coplanar, where a→ , b→ and c→ are unit (or any) vectors, then:
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a
xy+3zx−3x=4
b
2xy−2zx−3z−4=0
c
4xy−3zx+3z=4
d
xy−2zx+3z−4=0
answer is D.
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Detailed Solution
Conditions of coplanarity, coplanar vectors have scalar triple product as zero A→.(B→×C→)=0 or |x−23−2y−40−z2|=0 or x(2y−4z)+2(−4−0)+3(2z−0)=0 or 2xy−4zx−8+6z=0 or xy−2zx+3z−4=0