Questions
If time of flight of a projectile is 10 s. Range is 500 m. The maximum height attained by it will be
a
125 m
b
50 m
c
100 m
d
150 m
detailed solution
Correct option is A
Time of flight, T=2usinθg=10 s⇒ usinθ = 50 ms-1∴ H=u2sin2θ2g=(usinθ)22g=50×502×10=125 mTalk to our academic expert!
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