Question

If time of flight of a projectile is 10 s. Range is 500 m. The maximum height attained by it will be

Moderate

Solution

Time of flight, $T = \frac{2 u \sin θ}{g} = 10 s$
$\Rightarrow u sinθ = 50 {ms}^{- 1}$
$∴ H = \frac{u^{2} \sin^{2} θ}{2 g} = \frac{(u \sin θ)^{2}}{2 g} = \frac{50 \times 50}{2 \times 10} = 125 m$

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