Questions
If the time period of a two meter long simple pendulum is 2s, the acceleration due to gravity at the place where pendulum is executing S.H.M. is:
detailed solution
Correct option is A
T=2πℓgpla ⇒2=2πℓgpla ⇒g=π2ℓ ⇒g=2π2Talk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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