If a transparent medium of refractive index μ=1.5 and thickness t=2.5×10−5m is inserted in front of one of the slits of Young's Double Slit experiment, how much will be the shift in the interference pattern? The distance between the slits is 0.5 mm and that between slits and screen is 100 cm
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
5 cm
b
2.5 cm
c
0.25 cm
d
0.1 cm
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Shift in the fringe pattern x=(μ−1)t.Dd=(1.5−1)×2.5×10−5×100×10−20.5×10−3=2.5cm.