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If two anti-nodes are observed on either side of C, the frequency of the mode in which the rod is vibrating will be () length of the rod is 2.5 m
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Correct option is B
Velocity of the longitudinal waves in the rod =v=Y/d=2×1011/8000=5000 m/sThe wavelength of the wave for the mode of vibration in which 2 anti-nodes occur, is λ=1.253/4=53mHence frequency of vibration =n=Vλ=50005/3Hz=3000HzTalk to our academic expert!
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