Q.

If two anti-nodes are observed on either side of C, the frequency of the mode in which the rod is vibrating will be (y=2×1011N/m2,  d=8×103kg/m3) length of the rod is 2.5 m

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a

1000 Hz

b

3000 Hz

c

7000 Hz

d

1500 Hz

answer is B.

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Detailed Solution

Velocity of the longitudinal waves in the rod =v=Y/d=2×1011/8000=5000 m/sThe wavelength of the wave for the mode of vibration in which 2 anti-nodes occur, is  λ=1.253/4=53mHence frequency of vibration  =n=Vλ=50005/3Hz=3000Hz
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