If two balls, each of mass 0.06 kg, moving in opposite directions with speed 4 m/s, collide and rebound with the same speed, then the impulse imparted to each ball due to other is
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a
0.48 kg-m/s
b
0.53 kg-m/s
c
0.81kg-m/s
d
0.92 kg-m/s
answer is A.
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Detailed Solution
The balls exchange velocity on collision initial momentum of each ball before collision=mv=0⋅06×4=0⋅24kg−m/s Final momentum of each ball after collision =m(−v)=0⋅06×(−4)=−0⋅24kg⋅m/s ∴ change in momentum = Initial momentum - Final momentum =0⋅24−(−0⋅24)=0⋅48kg−m/s