Questions
If two bulbs of wattage 25 and 100 respectively each rated at 220 volt are connected in series with the supply of 440 volt, which bulb will fuse ?
detailed solution
Correct option is B
Resistance of 25 watt bulbR1=V2P=(220)225=1936ΩResistance of 100 watt bulbR2=V2P=(220)2100=484ΩSeries resistance, R=R1+R2=2420ΩCurrent through series combinationi=(440)2420=211Potential difference across 25 watt bulbV1=R1×i=1936×(2/11)=352 volt Potential difference across 100 watt bulbV2=R2×i=484×(2/11)=88 volt Thus the bulb of 25 watt will be fused because it can tolerate only 220 V while the voltage across it is 352 voltTalk to our academic expert!
Similar Questions
A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
