If two bulbs of wattage 25 and 100 respectively each rated at 220 volt are connected in series with the supply of 440 volt, which bulb will fuse ?

Resistance of 25 watt bulbR1=V2P=(220)225=1936ΩResistance of 100 watt bulbR2=V2P=(220)2100=484ΩSeries resistance, R=R1+R2=2420ΩCurrent through series combinationi=(440)2420=211Potential difference across 25 watt bulbV1=R1×i=1936×(2/11)=352 volt Potential difference across 100 watt bulbV2=R2×i=484×(2/11)=88 volt Thus the bulb of 25 watt will be fused because it can tolerate only 220 V while the voltage across it is 352 volt